Solve the following simultaneous linear equatioans
x = 6 - y
3x = 20 - 4y
Solution : SUBSTITUTION METHOD
x = 6 - y -------------(1)
3x = 20 - 4y -------------(2)
Substitute (1) into (2)
3(6 - y) = 20 - 4y
18 - 3y = 20 - 4y
-3y + 4y = 20 - 18
y = 2
From (1) subtitute y = 2
x = 6 - 2
x = 4
No comments:
Post a Comment